hw3, Q4

hw3, Q4

by Laura Koth -
Number of replies: 6

I am missing something with this question because I do not understand question 4g which says to Discuss how the answers to parts b and f differ.

I got the same answer for both b and f, so I must be missing a teaching point.

can anyone help explain the point of b and f?

thank you

In reply to Laura Koth

Re: hw3, Q4

by Thomas Newman -

If you got the same answer for b & f you most likely made a math error or got the same LR for parts A and E.  Review the chapter and/or Michael's lecture to see how to avoid that mistake.

In reply to Thomas Newman

Re: hw3, Q4

by Laura Koth -

thanks, the point is that i reviewed the chapter and I am not understanding why the two questions are different.

in both cases the pre test risk is >5% so, I don't understand what is being asked

In reply to Laura Koth

Re: hw3, Q4

by Chi Chu -

I'm not sure if this was the confusion, but the underlying premise of the question is that she should get a CTPA if her post-test probability after d-dimer is >= 5%. 

The question makes you do the calculation to obtain LR associated with the d-dimer result in 2 different ways. Using 2 different LR results and the same pretest probability of 10% is supposed to give you 2 different post-test probabilities.

In reply to Laura Koth

Re: hw3, Q4

by Thomas Newman -

Thank you for clarifying.  I think I understand your confusion now.  I've changed the stem of the question to clarify, adding "(post-test)" in the sentence below:

For this problem, we will say we should do a CTPA if the (post-test) probability of PE is ≥ 5%.

Does that help?

Tom

In reply to Thomas Newman

Re: hw3, Q4

by Jean Digitale -

This is not relevant to solve the question, but can you explain how the 32 corresponds to the 5% in the question stem as pasted below? I tried to do the calculations based on the chapter, but am missing something on how these two numbers relate.

"We will say we should do a CTPA if the probability of PE is ≥ 5%, i.e., we are willing to do up to 32 CTPAs to diagnose one PE".

Thanks!

In reply to Jean Digitale

Re: hw3, Q4

by Thomas Newman -

Dear Jean,

You aren't missing anything; it's a typo.  I'm guessing in a previous version of the problem the treatment threshold was 3%, in which case it should have said you are willing to do up to 32 CTPAs in patients without a PE to diagnose one PE.

In any case, assume the 5% threshold is right, in which case you are willing to do 20 CTPAs to diagnose one PE.

Tom